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Number of integral values of  b  for which tangent parallel to line \mathrm{y=x+1}  can be drawn to hyperbola  \mathrm{\frac{x^2}{5}-\frac{y^2}{b^2}=1} is 

Option: 1

0


Option: 2

1


Option: 3

2


Option: 4

None of these


Answers (1)

best_answer

Equation of tangent to hyperbola \mathrm{\frac{x^2}{5}-\frac{y^2}{b^2}=1} having slope m is

\mathrm{y=m x \pm \sqrt{a^2 m^2-b^2} \Rightarrow y=x \pm \sqrt{5-b^2}}

Comparing with \mathrm{y=x+1}, we get

\mathrm{b^2=4 \text { or } b= \pm 2 }

So, two values are possible.

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Anam Khan

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