Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Octahedral complexes of   undergo structural distortion <img

Octahedral complexes of  \mathrm{copper(II) } undergo structural distortion \mathrm{(Jahn-Teller).}
Which one of the given \mathrm{copper (II) } complexes will show the maximum structural distortion? \mathrm{(en - ethylenediamine;\mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{NH}_{2} ) }

Option: 1

\left[\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{SO}_{4}


Option: 2

\left[\mathrm{Cu}(\mathrm{en})\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right] \mathrm{SO}_{4}


Option: 3

\operatorname{cis}-\left[\mathrm{Cu}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]


Option: 4

\mathrm{\text { trans- }\left[\mathrm{Cu}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]}


Answers (1)

best_answer

Electronic configuration of \mathrm{Cu\left ( II \right )} is \mathrm{d^{9}}


The maximum John-Teller distortion will be shown maximum by  \mathrm{\left[\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{SO}_{4}}  , as \mathrm{\mathrm{H}_{2} \mathrm{O}}  is ,monodentate ligand. While in other complexes ethylenediamine (en) is present which forms chelate and due to chelotion,  distortion is lessened because ring Strain  can happen.

Hence option (A) is correct.

Posted by

Sanket Gandhi

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

NTA finds errors in JEE Main 2025 photos; asks to upload correct images by January 17
anam-khan

JEE Main 2025 Live: NTA finds errors in images, starts application correction; photo requirements
anam-khan

NTA Exams 2025 Live: NEET UG date, registration form soon at neet.nta.nic.in; UGC NET revised schedule out

Latest Question