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Octahedral complexes of  \mathrm{copper(II) } undergo structural distortion \mathrm{(Jahn-Teller).}
Which one of the given \mathrm{copper (II) } complexes will show the maximum structural distortion? \mathrm{(en - ethylenediamine;\mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{NH}_{2} ) }

Option: 1

\left[\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{SO}_{4}


Option: 2

\left[\mathrm{Cu}(\mathrm{en})\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right] \mathrm{SO}_{4}


Option: 3

\operatorname{cis}-\left[\mathrm{Cu}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]


Option: 4

\mathrm{\text { trans- }\left[\mathrm{Cu}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]}


Answers (1)

best_answer

Electronic configuration of \mathrm{Cu\left ( II \right )} is \mathrm{d^{9}}


The maximum John-Teller distortion will be shown maximum by  \mathrm{\left[\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{SO}_{4}}  , as \mathrm{\mathrm{H}_{2} \mathrm{O}}  is ,monodentate ligand. While in other complexes ethylenediamine (en) is present which forms chelate and due to chelotion,  distortion is lessened because ring Strain  can happen.

Hence option (A) is correct.

Posted by

Sanket Gandhi

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