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  • of <img alt="\mathrm{NaOH}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%

5 \mathrm{~g} of \mathrm{NaOH} was dissolved in deionized water to prepare a 450 \mathrm{~mL} stock solution this solution would be required to prepare 500 \mathrm{~mL} of 0.1 \mathrm{M} solution?
Given: Molar Mass of \mathrm{Na}, \mathrm{O} and \mathrm{H} is 23,16 and 1 \mathrm{~g} \mathrm{~mol}^{-1}respectively

Option: 1

180


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Molarity of stock solution
=\frac{5 / 40}{450} \times 1000
=\frac{50}{4 \times 45}=\frac{10}{36} \mathrm{M}

\mathrm{M}_1 \mathrm{~V}_1=\mathrm{M}_2 \mathrm{~V}_2

\frac{10}{36} \times \mathrm{V}=0.1 \times 500
\mathrm{~V}=\frac{50 \times 36}{10}=180 \mathrm{ml}

Posted by

Anam Khan

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