Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Of the following four aqueous solutions,total number of those solutions whose freezing point is lower than that of <img alt="\mathrm{0.10\, M\, C_{2}H_{5}OH}" src="https://entrancecorner.codecogs.com/gif.latex?%5Cmathrm%7B0.10%5C%2C%20M%5C%2C%20C_%7B2%7DH

Of the following four aqueous solutions,total number of those solutions whose freezing point is lower than that of \mathrm{0.10\, M\, C_{2}H_{5}OH} is __________ (Integer answer)  \mathrm{(i)\: 0. 10\, M\ Ba_{3}\left ( PO_{4} \right )_{2}}
 \mathrm{(ii)\: 0.10\, M\ Na_{2}SO_{4}}
\mathrm{(iii)\: 0. 10\, M\ KCl}
\mathrm{(iv)\: 0.10\,M\ Li_{3}PO_{4}}
 

Answers (1)

best_answer

As we have learnt ,

\mathrm{\Delta T_{f}= i\, K_{f}\: \: m}
So, greater the value of 'i' , greater will be the depression in freezing point and lower will be the value of the freezing point.

\mathrm{(i)\; Ba_{3}\left ( PO_{4} \right )_{2},\;\;\;i= 5}
\mathrm{(ii)\;Na_{2}SO_{4},\;\;\;i= 3}
\mathrm{(iii)\;KCl,\;\;\;i= 2}
\mathrm{(iv)\;Li_{3}PO_{4},\;\;\;i= 4}

Thus, all given compounds have a greater value of van't Hoff factor than \mathrm{C_{2}H_{5}OH\left ( i= 1 \right )}

Hence, the correct answer is 4

Posted by

sudhir.kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: Most important chapters for physics, chemistry, mathematics to score good marks
anam-khan

JEE Main 2025 session 2 dates clash with ISC, PSEB 12th exams; no impact on major science subjects
anam-khan

Delhi police EOW books FIITJEE for fraud; 192 complaints filed

Latest Question