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\mathrm{SO}_{2} \mathrm{Cl}_{2} on reaction with excess of water results into acidic mixture

\mathrm{SO}_{2} \mathrm{Cl}_{2}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{H}_{2} \mathrm{SO}_{4}+2 \mathrm{HCl}

16 moles of \mathrm{NaOH} is required for the complete neutralisation of the resultant acidic mixture. The number of moles of \mathrm{SO}_{2} \mathrm{Cl}_{2} used is :

 

Option: 1

16
 


Option: 2

8


Option: 3

4

 


Option: 4

2


Answers (1)

best_answer

Reaction given,

\Rightarrow 4 mole of \mathrm{H}^{+} are produced from 1 mol of \mathrm{SO}_{2} \mathrm{Cl}_{2}

\Rightarrow We know For 1 mole of  \mathrm{H}^{+} required 1 mol of \mathrm{NaOH} for complete neutralisation.

\Rightarrow For 16 mol \mathrm{H^{+}=16} mole of \mathrm{NaOH}

Now,

16 mole of \mathrm{H^{+}} are produced from \left ( \mathrm{\frac{16}{4}\times 1} \right ) mole \mathrm{SO}_{2} \mathrm{Cl}_{2}

So, 4 mole of  \mathrm{SO}_{2} \mathrm{Cl}_{2} is used.

Hence, the correct answer is option (3).

Posted by

Ajit Kumar Dubey

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