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One end of a uniform wire of length L and weight w, is attached rigidly to a point in the roof, and a weight w, is suspended from its lower end. If s is the area of cross-section of the wire, the stress in the wire at a height of \frac{3L}{4} from its lower end is -

Option: 1

\frac{W_1}{S}


Option: 2

\frac{W_1 +\frac{W}{4}}{S}


Option: 3

\frac{W_1 +\frac{3W}{4}}{S}


Option: 4

\frac{W_1 +W}{S}


Answers (1)

best_answer

At length \frac{3L}{4} from the lower end, tension in the wire,

T = Suspended load + \frac{3}{4} weight of wire

T = W_1 + \frac{3W}{4}

Stress = \frac{T}{S} = \frac{W_1 + \frac{3W}{4}}{S}

Posted by

Devendra Khairwa

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