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One kg of a diatomic gas is at a pressure of 8\times 10^{4}N/m^{2}. The density of the gas is 4\; kg/m^{3}. What is the energy of the gas due to its thermal motion?

Option: 1

3\times 10^{4}\; J


Option: 2

5\times 10^{4}\; J


Option: 3

6\times 10^{4}\; J


Option: 4

7\times 10^{4}\; J


Answers (1)

best_answer

As we have learnt,

 

Enthalpy of Vapourisation -

Amount of enthalpy change to vapourise 1 mole liquid completely at its boiling point.

- wherein

At\: 100\: c^{\circ}

H_{2}O_{(l)}\rightarrow H_{2}O_{(g)}

\Delta H_{vapourisation}= 40.6\, KJ/Mole

 

 H_2 O_{(l)}\overset{100\degree C} {\rightleftharpoons } H_2 O_{(g)}

\Delta n_{(g)} = 1 - 0 = 1

As we know, \Delta H^o_{vap} = \Delta E^o_{vap} + \Delta n_{(g)}RT

\\*\Rightarrow 40.66 kJ\cdot mol^{-1} = \Delta E^o_{vap} + 8.314\times 10^{-3}\times 373 \\*\Rightarrow \Delta E^o_{vap} = + 37.56 kJmol^{-1}

 

Posted by

Gautam harsolia

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