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  • Please help! A charge (– q) and another charge (+Q) are kept at two points A and B respectively. Keeping the charge (+Q) fixed at B, the charge (– q) at A is moved to another point C such that ABC forms an equilateral triangle of side l.

A charge (– q) and another charge (+Q) are kept at two points A and B respectively. Keeping the charge (+Q) fixed at B, the charge (– q) at A is moved to another point C such that ABC forms an equilateral triangle of side l. The network done in moving the charge (– q) is

  • Option 1)

    \frac{1}{4\pi \varepsilon _{0}}\frac{Qq}{l}

     

     

  • Option 2)

    \frac{1}{4\pi \varepsilon _{0}}\frac{Qq}{l^{2}}

  • Option 3)

    \frac{1}{4\pi \varepsilon _{0}}Qql

  • Option 4)

    Zero

 

Answers (1)

As we leaned

 

Potential Difference -

V_{B}-V_{A}=\frac{w}{q}

-

 

 

Since V_{A}=V_{C}=\frac{kQ}{l}

So W=q(V_{c}-V_{A})=0


Option 1)

\frac{1}{4\pi \varepsilon _{0}}\frac{Qq}{l}

 

 

Option 2)

\frac{1}{4\pi \varepsilon _{0}}\frac{Qq}{l^{2}}

Option 3)

\frac{1}{4\pi \varepsilon _{0}}Qql

Option 4)

Zero

Posted by

Vakul

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