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A metal wire  having resitance R ,stretched in such a way that its radius become half. New value of resistance is

  • Option 1)

    16R

  • Option 2)

    R/16

  • Option 3)

    4R

  • Option 4)

    R/4

 

Answers (1)

best_answer

As we learnt

 

Ratio of resistances -

 

If radius is given

R\alpha\frac{1}{r^{4}}

- wherein

\frac{R_{1}}{R_{2}}= \left ( \frac{r_{2}}{r_{1}} \right )^{4}

 

 

 

Since R is proportional to 1/r4(r=radius of the wire)

As r is halved , the resistance become 16 times.


Option 1)

16R

Option 2)

R/16

Option 3)

4R

Option 4)

R/4

Posted by

Aadil

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