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The value of m, \: log_{e}(m-3)<1 is

  • Option 1)

    (0,3)

  • Option 2)

    (0,e)

  • Option 3)

    (0,e+3)

  • Option 4)

    (3,3+e)

 

Answers (1)

best_answer

As learnt in concept

Logarithmic Function -

f\left ( x \right )= \log\: _{a}x

base:a> 0,a\neq 1

domin:x> 0

Range:f\left ( x \right )\in R

- wherein

 

 

\log_{e}(m-3)<1

m-3<e^{1}\:\:\:\:\:\:\:\:\Rightarrow m <3+e

Also, m-3>0\:\:\:\:\:\:\:\:\Rightarrow m >3

Thus, m \:\epsilon(3,3+e)

 


Option 1)

(0,3)

This option is incorrect.

Option 2)

(0,e)

This option is incorrect.

Option 3)

(0,e+3)

This option is incorrect.

Option 4)

(3,3+e)

This option is correct.

Posted by

prateek

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