# The equivalent conductivity of KCl at infinite dilution is 130 $mho cm^2/eq$. The transport number of $Cl^-$ ion in KCl at the same temperature is 0.505. The transport number of $K^+ ion\: is$  Option 1) $0.495$ Option 2) $0.505$ Option 3) $0.0495$ Option 4) Can't be determined

As we learnt in

Conductivity -

Inverse of resistivity is called conductivity. $\kappa = \frac{1}{\rho }$

- wherein

SI unit of Conductivity = $Sm^{-1}$

Transport number of $Cl^{-}=0.505$

but $t_{cl^{-}}+t_{k^{+}}=1$

$t_{k^{+}}=1-0.505=0.495$

$\therefore$ Solution is 1

Option 1)

$0.495$

Correct

Option 2)

$0.505$

Incorrect

Option 3)

$0.0495$

Incorrect

Option 4)

Can't be determined

Incorrect

### Preparation Products

##### Knockout BITSAT 2021

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 2999/-