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What volume of 3 molar HN0_3  is needed to oxidise of 8g of Fe^{2+} to Fe^{3+}? HNO_3 get converted to NO :

  • Option 1)

    8 ml

  • Option 2)

    16 ml

  • Option 3)

    32 ml

  • Option 4)

    64 ml

 

Answers (1)

best_answer

As we learnt in 

Oxidation -

It is defined as the addition of oxygen / electronegative element to a substance or removal of hydrogen / electropositive element from a substance.

- wherein

e.g. 2H_{2}S(g) + O_{2}(g)\rightarrow 2S(s)+2H_{2}O(l)

 

 \underset{77g}{HNO_{3}}+\underset{168g}{3Fe^{2+}}\rightarrow 3Fe^{3+}+side\, \,products

Now 168g of Fe^{2+}\rightarrow 77g\, \, HNO_{3}

8gFe^{2+}\rightarrow \frac{77\times 8}{168}=3.67g

Molarity (given)=3M

3=\frac{w\times 1000}{mV}

V=\frac{3.67\times 1000}{mV}

V=\frac{3.67\times 1000}{3\times 77}= 15.88ml\sim 16ml

\therefore Solution is 2


Option 1)

8 ml

Incorrect

Option 2)

16 ml

Correct

Option 3)

32 ml

Incorrect

Option 4)

64 ml

Incorrect

Posted by

Aadil

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