For the reaction, CO_{(g)}+Cl_{2(g)}\rightleftharpoons COCl_{2(g)}    the   K_{p}/K_{c}   is equal to

  • Option 1)

    1/RT

  • Option 2)

    RT

  • Option 3)

    \sqrt{RT}

  • Option 4)

    1.0

 

Answers (1)

As we learnt in 

Relation between Kp and Kc -

K_{p}=K_{c}(RT)^{\bigtriangleup n}

while calculating the value of Kp , pressure should be expressed in bar.

1\:bar=10^{5}pa

- wherein

\bigtriangleup n = (number of moles of gaseous products) - (number of moles gaseous reaction)

 

 

 

CO_{(g)}+Cl_{2(g)}\rightleftharpoons COCl_{2(g)}

K_{p}=K_{c}(RT)^{-1}

\frac{K_{p}}{K_{c}}=\frac{1}{RT}

 


Option 1)

1/RT

This option is correct

Option 2)

RT

This option is incorrect

Option 3)

\sqrt{RT}

This option is incorrect

Option 4)

1.0

This option is incorrect

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