# A system of three polarizers $P_{1},P_{2},P_{3}$ is set up such that the pass axis of $P_{3}$ is crossed with respect to that of $P_{1}$. The pass axis of $P_{2}$ is inclined at $60^{\circ}$ to the pass axis of $P_{3}$. When a beam of unpolarized light of intensity $I_{o}$ is incident on $P_{1}$, the intensity of light transmitted by the three polarizers is I. The ratio $(I_{o}/I)$ equal (nearly): Option 1) 5.33 Option 2) 16.00 Option 3) 10.67 Option 4) 1.80

S solutionqc

Malus Law -

$I= I_{0}\cdot \cos ^{2}\theta$

$\theta =$ angle made by E vector with transmission axis.

- wherein

$I=$ Intensity of transmitted light after polarisation .

$I_{0}=$ Intensity of  incident light.

the intensity of light transmitted from $P_{1}=\frac{I_{o}}{2}$

the intensity of light transmitted from $P_{2}=\frac{I_{o}}{2}\cos ^{2}30=\frac{3I_{o}}{8}$

The intensity of light transmitted from $P_{3}$

$I=\frac{3I_{o}\cos ^{2}60}{8}=\frac{3I_{o}}{32}$

$\frac{I_{o}}{I}=\frac{32}{3}=10.67$

Option 1)

5.33

Option 2)

16.00

Option 3)

10.67

Option 4)

1.80

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