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Consider the voltaic cell based on these half cell Ag^+(aq ) + e^-\rightarrow Ag(s) ; E^0 = 0.80 V

Cd ^{2+ }(aq ) + 2e^- \rightarrow Cd(s) ; E^0 = -0.40 V

Which is the anode and what is the potential of the cell under standard conditions ?  

  • Option 1)

    Ag , E_{cell} = 0.40 V

  • Option 2)

    Ag , E_{cell} = 2.00 V

  • Option 3)

    Cd , E_{cell} = 1.20 V

  • Option 4)

    Cd , E_{cell} = 2.00 V

 

Answers (1)

As we have learned

Standard reduction potential -

It measure the tendency of a chemical species to acquire electrons and there by be reduced. It is measured in volts or mv.

-

 

 Anode has lower standard reduction potential thus , Cd will be considered as anode 

E_{cell}^{0}= E_{cathod}- E_{anode }= E_{Ag^+/Ag}- E_{Cd^{2+}/Cd }

= 0.80 - (-0.40) = 1.20 v


Option 1)

Ag , E_{cell} = 0.40 V

Option 2)

Ag , E_{cell} = 2.00 V

Option 3)

Cd , E_{cell} = 1.20 V

Option 4)

Cd , E_{cell} = 2.00 V

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