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Shown below is a distribution of charges. The flux of electric field due to these charges through the surface S is

  • Option 1)

    3q/\varepsilon _0

  • Option 2)

    2q/\varepsilon _0

  • Option 3)

    q/\varepsilon _0

  • Option 4)

    zero

 

Answers (1)

best_answer

As we have learned

Flux may be Positive Negative or zero -

For closed body.

- wherein

 

 \phi = Q_{enc}/\varepsilon _0= 2q/\varepsilon _0

 


Option 1)

3q/\varepsilon _0

Option 2)

2q/\varepsilon _0

Option 3)

q/\varepsilon _0

Option 4)

zero

Posted by

Aadil

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