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The number of electrons in 1.6 C charge will be

  • Option 1)

    10^{19}\; \;

  • Option 2)

    \; 10^{20}\; \;

  • Option 3)

    \; 1.1\times 10^{19}\; \;

  • Option 4)

    \; 1.1\times 10^{2}

 

Answers (2)

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As we learned

Quantization of charge -

Charge on any body will be some integral multiple of e.

 

- wherein

Q=\pm ne

n = 1, 2, 3, ......

 

 n=\frac{q}{e}=\frac{1.6}{1.6\times 10^{-19}}=10^{19}

 


Option 1)

10^{19}\; \;

Option 2)

\; 10^{20}\; \;

Option 3)

\; 1.1\times 10^{19}\; \;

Option 4)

\; 1.1\times 10^{2}

Posted by

Avinash

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JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Use the formula Q=ne

Then substitute Q=1.6C

And e=1.6x10^-19

 

 

Posted by

Arvind

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