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The pair of species that has the same bond order in the following is:

  • Option 1)

    O_{2},B_{2}

  • Option 2)

    CO, NO^{+}

  • Option 3)

    NO^{-}, CN^{-}

  • Option 4)

    O_{2},N_{2}

 

Answers (1)

best_answer

As we learnt in

Bond Order -

Bond order is defined as one half the difference between the number of electrons present in the bonding and the antibonding orbitals.

- wherein

Bond \:Order=\frac{N_{b}-{N_{a}}}{2}

 

 Electronic configuration of CO molecule:

\sigma 2 s^{2}\; \sigma^{*}\; 2s^{2}\; \pi 2p_x^{2}\; \pi 2 p_y^{2}\; \sigma 2 p_z^{2}

Bond order = \frac{1}{2}(8-2)=3

Electronic configuration of NO^{+} molecule:

\sigma 2 s^{2}\; \sigma^{*}\; 2s^{2}\; \pi 2p_x^{2}\; \pi 2 p_y^{2}\; \sigma 2 p_z^{2}

\therefore  Bond order = \frac{1}{2}(8-2)=3

 


Option 1)

O_{2},B_{2}

This option is incorrect.

Option 2)

CO, NO^{+}

This option is correct.

Option 3)

NO^{-}, CN^{-}

This option is incorrect.

Option 4)

O_{2},N_{2}

This option is incorrect.

Posted by

prateek

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