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.The work done in bringing a 20 coulomb charge from point A to point B for distance 0.2m is 2J. The potential difference between the two points will be (in volt)

  • Option 1)

    0.2

  • Option 2)

    8

  • Option 3)

    0.1

  • Option 4)

    0.4

 

Answers (1)

As we have learned

when Charged Particle at rest in uniform field -

W=Q\cdot \Delta v

-

 

 

By using W = Q\Delta v\Rightarrow \Delta v=2/20=0.1volt


Option 1)

0.2

Option 2)

8

Option 3)

0.1

Option 4)

0.4

Posted by

Vakul

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