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Engineering

Please help! - Trigonometry - JEE Main-8

Two poles are standing on a horizantal ground are of heights 5\:m\:\:and\:\:10\:m respectively . The line joining their tops makes an angle of 15^{0} with the ground . Then the distance ( in m ) between the poles, is :

  • Option 1)

    5(2+\sqrt{3})

  • Option 2)

    5(\sqrt{3}+1)

  • Option 3)

    \frac{5}{2}(2+\sqrt{3})

  • Option 4)

    10(\sqrt{3}-1)

Answers (1)
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V Vakul

 

 

\\\tan\:15=\left ( \frac{5}{n} \right )\:\:\:\:\:\:\:\:\:\:n=height\\\\\:2-\sqrt{3}=\frac{5}{n}

\\n=\frac{5}{2-\sqrt3}\times\frac{2+\sqrt{3}}{2+\sqrt{3}}=\frac{5(2+\sqrt{3})}{(1)}\\\\\:n=5\left ( 2+\sqrt{3} \right )


Option 1)

5(2+\sqrt{3})

Option 2)

5(\sqrt{3}+1)

Option 3)

\frac{5}{2}(2+\sqrt{3})

Option 4)

10(\sqrt{3}-1)

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