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  • Please,please help me - Complex numbers and quadratic equations - JEE Main-8

If \left | z-4 \right |< \left | z-2 \right |, its solution is given by

  • Option 1)

    Re\left ( z \right )> 0

  • Option 2)

    Re\left ( z \right )< 0

  • Option 3)

    Re\left ( z \right )> 3

  • Option 4)

    Re\left ( z \right )>2

 

Answers (2)

best_answer

As we have learned

Perpendicular bisector -

Locus of point equidistant from two given points.

\left |z-z_{1} \right |=\left |z-z_{2} \right |

z will lie on perpendicular bisector of line joining z_{1} and z_{2} .

- wherein

z_{1} and z_{2} are any two fixed points . z is a moving point in the plain which is equidistant from z_{1} and z_{2} .so z will lie on perpendicular bisector

 

 

As seen in figure 

 Re(z) > 3 

 

 

 

 


Option 1)

Re\left ( z \right )> 0

Option 2)

Re\left ( z \right )< 0

Option 3)

Re\left ( z \right )> 3

Option 4)

Re\left ( z \right )>2

Posted by

Himanshu

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