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  • Please,please help me Equation of plane parallel to 2x-3y+4z+5=0 and also passing through (1,1,1) is

Equation of plane parallel to 2x-3y+4z+5=0 and also passing through (1,1,1) is 

  • Option 1)

    2x-3y+4z=3

  • Option 2)

    2x+3y-5z=0

  • Option 3)

    x+2y-3z=0

  • Option 4)

    x+4y+5z=10

 

Answers (1)

best_answer

As we have learned

Equation of plane parallel to given plane -

The equation of plane parallel to 

ax+by+cz+d= 0 is given by

ax+by+cz+k= 0

-

 

 Required plane will be of form 2x-3y+4z+k=0 But it will satisfy (1,1,1) so on putting it, we get k=-3 

\therefore 2x-3y+4z=3 is the required plane 


Option 1)

2x-3y+4z=3

Option 2)

2x+3y-5z=0

Option 3)

x+2y-3z=0

Option 4)

x+4y+5z=10

Posted by

Himanshu

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