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The molar solubility ( in mol L -1) of a sparingly soluble salt MX_{4} is s  . The corresponding solubility product is  K_{sp}.s is given in terms of  K_{sp} by the relation

  • Option 1)

    s=\left ( K_{sp}/128 \right )^{1/4}

  • Option 2)

    s= \left ( 128K_{sp} \right )^{1/4}

  • Option 3)

    s= \left ( 256K_{sp} \right )^{1/5}

  • Option 4)

    s=\left ( K_{sp}/256 \right )^{1/5}

 

Answers (1)

best_answer

As we learnt in 

General expression of solubility product -

M_{x}X_{y}\rightleftharpoons xM^{p+}(aq)+yX^{2-}(aq)


(x.p^{+}=y.\bar{q})

- wherein

Its solubility product is 
 

K_{sp}=[M^{p+}]^{x}\:[X^{2-}]^{y}

 

 

MX_{4}(s)\rightleftharpoons M^{4+}_{aq}+4X^{-}_{(aq)}

                          s                  4s

Solubility\: product\: ,K_{sp}= s\times \left ( 4s \right )^{4}= 256\: s^{5}

\therefore \: \: \: \: s= \sqrt[5]{\frac{K_{sp}}{256}}= \left ( \frac{K_{sp}}{256}\right )^{1/5}

 


Option 1)

s=\left ( K_{sp}/128 \right )^{1/4}

This option is incorrect

Option 2)

s= \left ( 128K_{sp} \right )^{1/4}

This option is incorrect

Option 3)

s= \left ( 256K_{sp} \right )^{1/5}

This option is incorrect

Option 4)

s=\left ( K_{sp}/256 \right )^{1/5}

This option is correct

Posted by

divya.saini

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