In a statistical investigation of 1003 families of Chandigarh it was found that 63 families has neither a phone nor a TV, 794 families has none and 187 has a TV. the number of families in that group having both a phone and a TV Option 1) 36 Option 2) 41 Option 3) 32 Option 4) None of these.

As we learnt in

Number of Elements in Union A & B -

n (A ∪ B) = n (A) + n (B) – n (A ∩ B)

- wherein

Given A and B be any finite sets. then Number of Elements in union A & B is given by this formula.

n(phone) =794                   n(TV)=187

Families having eaither phone or TV

=1003 - 63=940

$\\Thus\: \: 940=794+187-\left n( P\cap T \right )\\*\\*n\left ( P\cap T \right )=41$

Option 1)

36

Incorrect

Option 2)

41

Correct

Option 3)

32

Incorrect

Option 4)

None of these.

Incorrect

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