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Presence of $Hg_2^{2+}$ ion can be confirmed by the reagent?
Option: 1
$SnCl_2$

Option: 2
$NH_3$

Option: 3
Both a & b

Option: 4
$H_2SO_4$ in water

Answers (1)

best_answer

As we have learnt,

$HgCl_{2}$ is reduced by $SnCl_{2}$

$HgCl_{2}+SnCl_{2}\rightarrow Hg_{2}Cl_{2} + SnCl_{4}$

$Hg_{2}Cl_{2}+SnCl_{2}\rightarrow 2Hg + SnCl_{4}$

Also,

With $NH_3,Hg_2^{2+}$ forms black ppt of $Hg$

$Hg_{2}Cl_{2} + NH_{3}\rightarrow Hg(NH_{2})Cl + Hg (black\: ppt)$

Thus, $Hg_2^{2+}$ can be detected by $SnCl_2$ as well as $NH_3$

Hence, the correct answer is Option (3)

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Anam Khan

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