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  • Pressure of 1 g of an ideal gas A at  is found to be 2 bar.

Pressure of 1 g of an ideal gas A at \mathrm{27 ^{\circ}C} is found to be 2 bar. when 2g of another ideal gas B is introduced in the same flask at same temperature, the pressure becomes 3 bar . Find  a relationship between their molecular masses _______

Option: 1

\frac{2}{4}


Option: 2

\frac{3}{9}


Option: 3

\frac{1}{4}


Option: 4

\frac{9}{17}


Answers (1)

Suppose, the molar masses of gases A and B are \mathrm{M_A} and \mathrm{M_B} g/mol respectively.

1 g of \mathrm{A=\frac{1}{M_A} \mathrm{~mol}} of A and 2g of

\mathrm{B=\frac{2}{M_B} \operatorname{mol} \text { of } B}

Using ideal gas equation  \mathrm{(P V=n R T)} for the gas A and the gas mixture of A and B , We have -----

\mathrm{\begin{aligned} & 2 \times v=\frac{1}{M_A} R T \longrightarrow \\ & 3 \times V=\left(\frac{1}{M_A}+\frac{2}{M_B}\right) R T\end{aligned}}

from dividing equation (2) by (1) , we have ------

\mathrm{1.5=\frac{M_B+2 M_A}{M_B} \Rightarrow 2 M_A=0.5 M_B \Rightarrow \frac{M_A}{M_B}=\frac{1}{4}}

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Kshitij

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