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  • Question : Entropy Change and Heat Transfer A container of gas at a temperature of 300 K is heated, and its volume increases from <img alt="\mathrm{0.03 \; m^{3}}" src="h

Question : Entropy Change and Heat Transfer

A container of gas at a temperature of 300 K is heated, and its volume increases from \mathrm{0.03 \; m^{3}} to \mathrm{0.06 \; m^{3}}. If 800 J of heat is added to the gas during the process, calculate the change in entropy of the gas.

Option: 1

2.67J
 


Option: 2

1.70 J
 


Option: 3

2.200 J


Option: 4

2.20 J


Answers (1)

best_answer

The change in entropy (\Delta S) can be calculated using the formula:

\mathrm{\Delta S=\frac{Q}{T}}

Given

Q = 800 J (heat added)
T = 300 K (temperature)

Calculate the change in entropy:

\mathrm{\begin{aligned} \Delta S & =\frac{Q}{T} \\ \Delta S & =\frac{800 \mathrm{~J}}{300 \mathrm{~K}} \\ \Delta S & \approx 2.67 \mathrm{~J} / \mathrm{K} \end{aligned}}

Therefore, the correct option is A.

 

Posted by

Ritika Kankaria

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