Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Solve! Calculate the molality of a solution containing of Acetic acid in Ethanol if the mass of solute = 10g and the density of Ethanol = 0.789 gmL-1.

Calculate the molality of a solution containing of Acetic acid in Ethanol if the mass of solute =  10g and the density of Ethanol = 0.789 gmL-1.

  • Option 1)

    0.2112

  • Option 2)

    0.2012

  • Option 3)

    0.1992

  • Option 4)

    0.2002

 

Answers (1)

best_answer

We know.

Molality (m) = (number of moles of solute)/(mass of solvent in kg)

Now,

Moles of solute Acetic acid  = mass / molar mass

 \mathrm{= \frac{10}{60}\ moles}

If Volume of ethanol = 1 L

Formula, Density = mass/volume

So,

Weight of ethanol = 1000 x 0.789 = 789g = 0.789 Kg

\mathrm{Molality = \frac{mass\;of\;solute}{mass\;of\;solution\ in\ kg } }

\mathrm{Molality = \frac{10}{60\times\frac{789}{1000}} = 0.2112\ m/kg}


Option 1)

0.2112

Option 2)

0.2012

Option 3)

0.1992

Option 4)

0.2002

Posted by

divya.saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 paper 2 final answer key out; NTA drops 4 questions, 2 from BPlanning
anam-khan

JEE Main 2025 session 2 answer key out for BArch, BPlanning; response sheet on jeemain.nta.nic.in
anam-khan

JEE Mains 2025 Paper 2 Answer Key LIVE: BArch final answer key PDF expected soon at jeemain.nta.nic.in

Latest Question