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The total number of possible isomers for the complex compound 

[Cu^{\mathbb{I}\mathbb{I}} (NH_{3})_{4}][Pt^{\mathbb{I}\mathbb{I}}Cl_{4}] are 

  • Option 1)

    3

  • Option 2)

    4

  • Option 3)

    5

  • Option 4)

    6

 

Answers (1)

As we have learned

Structural Isomerism -

These isomers have same molecular formula but different bonding patterns

- wherein

For example: M-NCS and M-SCN

 

 1   [Cu(NH_3)_4]\cdot [PtCl_4]

2    [Cu(NH_3)_3Cl]\cdot [PtCl_3(NH_3)]

3    [Cu(NH_3)_2Cl]\cdot [PtCl_2(NH_3)_2] .. cis

4    [Cu(NH_3)_2Cl]\cdot [PtCl_2(NH_3)_2] .. Trans

5    [Cu(NH_3)Cl_3]\cdot [PtCl(NH_3)_3]

6    [Pt(NH_3)_4Cl]\cdot [CuCl_4]

 

 

 

 

 


Option 1)

3

Option 2)

4

Option 3)

5

Option 4)

6

Posted by

Vakul

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