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If E  is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional  to  

  • Option 1)

    E\;

  • Option 2)

    \; E^{2}\;

  • Option 3)

    \; \frac{1}{E^{2}}\;

  • Option 4)

    \; E^{3}

 

Answers (1)

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As we learned

Electric Field -

The space around a charge in which another charged particle experiences a force is said to have electric field in it.

- wherein

 

 Electrostatic energy density \frac{dU}{dV}=\frac{1}{2}K\varepsilon _{0}E^{2}

 


Option 1)

E\;

Option 2)

\; E^{2}\;

Option 3)

\; \frac{1}{E^{2}}\;

Option 4)

\; E^{3}

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prateek

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