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An electric dipole of moment \vec{p} is placed normal to the lines of force of electric intensity \vec{E}then the work done in deflecting it through an angle of 180 \degree is

  • Option 1)

    pE

  • Option 2)

    +2pE

  • Option 3)

    -2pE

  • Option 4)

    zero

 

Answers (1)

best_answer

As we have learned

Torque Experienced by the dipole -

\vec{\tau }=\vec{P}\times \vec{E}

\vec{\tau }=PE\sin \Theta

\Theta =0^{\circ}    \tau =0

\Theta =\frac{\pi }{2}             \tau = max^{m}

- wherein

 

 

 

 Work done \int_{90}^{270}pE \sin \theta d\theta = \left [ -pE \cos \theta \right ]_{90}^{270}=0

 


Option 1)

pE

Option 2)

+2pE

Option 3)

-2pE

Option 4)

zero

Posted by

prateek

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