Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

In the given circuit the internal resistance of the 18V cell is negligible. If R₁ = 400 $\Omega$ , R₃ = 100 $\Omega$ and R₄ = 500 $\Omega$ and the reading of an ideal voltmeter across R₄is 5V, then the value of R₂will be:

Option 1)
450 $\Omega$
Option 2)
300 $\Omega$
Option 3)
550 $\Omega$
Option 4)
230 $\Omega$

Answers (1)

best_answer

Potentiometer -

It is a device used to measure e.m.f of a given cell and to compare e.m.f's of cells

- wherein

It is also used to measure internal resistance of given cell

Current through $500\Omega$ , $I_{2}=\frac{5}{500}=\frac{1}{100}A$

$\therefore$ Voltage across $100\Omega$ = $I_{2}R$

= $\frac{1}{100}\times 100$

= 1 V

So Voltage across $R_{2}=5+1=6V$

Voltage across $R_{1}=18-6=12V$

Current through $R_{1}$

$I=\frac{12}{400}=\frac{3}{100}$

Current through $R_{2}$

$I_{1}=I-I_{2}$

$=\frac{3}{100}-\frac{1}{100}$

$=\frac{2}{100}$

$R_{2}=\frac{6}{\frac{2}{100}}=300\Omega$

Option 1)

450 $\Omega$

Option 2)
300 $\Omega$
Option 3)

550 $\Omega$

Option 4)

230 $\Omega$

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 paper 2 final answer key out; NTA drops 4 questions, 2 from BPlanning

anam-khan

JEE Main 2025 session 2 answer key out for BArch, BPlanning; response sheet on jeemain.nta.nic.in

anam-khan

JEE Mains 2025 Paper 2 Answer Key LIVE: BArch final answer key PDF expected soon at jeemain.nta.nic.in

Latest Question