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A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be

  • Option 1)

    one fourth

  • Option 2)

    halved

  • Option 3)

    doubled

  • Option 4)

    four times

 

Answers (2)

best_answer

As we have learned

Power dissipiated in the external circuit -

(\frac{nE}{R+nr})^{2}\cdot R

-

 

 H = \frac{V^2}{R}t

Resistance of one part becomes 

R/2 

H ' = \frac{V^2}{R/2}t= 2(\frac{V^2 }{R}t)

H' = 2H 

 

 

 

 

 


Option 1)

one fourth

Option 2)

halved

Option 3)

doubled

Option 4)

four times

Posted by

Avinash

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