A spherical planet far out in space has a mass M0 and diameter D0. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity which is equal to

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Answers (1)

As we learnt in 

Acceleration due to gravity (g) -

Force extended by earth on a body is gravity.

Formula:    g=\frac{GM}{R^{2}},

g=\frac{4}{3}\pi \rho \, GR

g\rightarrow gravity

\rho \rightarrow density of earth

R \rightarrow Radius of earth


- wherein

It's average value is 9.8\: m/s^{2}\; \; or \; \; 981cm/sec^{2}\; or\; 32feet/s^{2} on the surface of earth


 Acceleration due to gravity=\frac{GM_{o}}{R_{o}^{2}}=\frac{GM_{o}}{\left ( \frac{D_{o}}{2} \right )^{2}}=\frac{4GM_{o}}{D_{o}^{2}}


Option 1)


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Option 2)


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Option 3)


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Option 4)


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