if \frac{1}{8!}+\frac{1}{9!}= \frac{x}{10!}  (where '!' denotes factorial)

Then x is equal to -

  • Option 1)

    100

  • Option 2)

    90

  • Option 3)

    170

  • Option 4)

    None of these

 

Answers (1)

As we learnt in 

Factorial Notation -

The product of first n natural numbers. n! = n(n - 1) (n - 2) ..........3 . 2 . 1

- wherein

Where n\epsilon N

 

 \frac{1}{8!}+\frac{1}{9!}=\frac{x}{10!}\\*\\= >x= \frac{10!}{8!}+\frac{10!}{9!}\\*\\*x=10\times 9+10\\*\\*x=100


Option 1)

100

Correct

Option 2)

90

Incorrect

Option 3)

170

Incorrect

Option 4)

None of these

Incorrect

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