For the reaction equilibrium,

N_{2}O_{4(g)}\rightleftharpoons 2NO_{2(g)} the concentrations of  N_{2}O_{4}\; and \; NO_{2}  at equilibrium are 4.8\times 10^{-2}\; and\; 1.2\times 10^{-2}\; mol\; L^{-1}\; respectively.

The\; value\; of\; K_{c}\; for\; the\; reaction \; is

  • Option 1)

    3.3\times 10^{2}\; mol\; L^{-1}

  • Option 2)

    3\times 10^{-1}\; mol\; L^{-1}

  • Option 3)

    3\times 10^{-3}\; mol\; L^{-1}

  • Option 4)

    3\times 10^{3}\; mol\; L^{-1}

 

Answers (1)

As we learnt in 

Law of Chemical equilibrium -

At a given temperature, the product of concentration of the reaction products raised to the respective stoichiometric coefficient in the balanced chemical equation divided by the product of concentration of the reactants raised to their individual stoichiometric coefficients has a constant value.

- wherein

aA+bB\rightleftharpoons cC+dD


K_{c}=\frac{[C]^{c\:[D]^{d}}}{[A]^{a}\:[B]^{b}}

[A],\:[B],\:[C]\:[D]

are equilibrium concentration

 

 N_{2}O_{4} \:_{(g)} \rightleftharpoons 2NO_{2} _{(g)}\:

4.8x10-2                       1.2\times 10^{-2}

K_{c}= \frac{(NO_{2})^{2}}{(N_{2O_{4})}}= \frac{(1.2\times 10^{-2})}{(4.8\times 10^{-2})}= 3\times 10^{-3} MoleL^{-1}


Option 1)

3.3\times 10^{2}\; mol\; L^{-1}

This option is incorrect 

Option 2)

3\times 10^{-1}\; mol\; L^{-1}

This option is incorrect 

Option 3)

3\times 10^{-3}\; mol\; L^{-1}

This option is correct 

Option 4)

3\times 10^{3}\; mol\; L^{-1}

This option is incorrect 

Most Viewed Questions

Preparation Products

Knockout JEE Main April 2021 (One Month)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 14000/- ₹ 4999/-
Buy Now
Knockout JEE Main May 2021

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 22999/- ₹ 9999/-
Buy Now
Test Series JEE Main May 2021

Unlimited Chapter Wise Tests, Unlimited Subject Wise Tests, Unlimited Full Mock Tests, Get Personalized Performance Analysis Report,.

₹ 6999/- ₹ 2999/-
Buy Now
Knockout JEE Main May 2022

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Live Classes, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 34999/- ₹ 24999/-
Buy Now
JEE Main Rank Booster 2021

Booster and Kadha Video Lectures, Unlimited Full Mock Test, Adaptive Time Table, 24x7 Doubt Chat Support,.

₹ 13999/- ₹ 6999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions