If the length of simple pendulum is increased by 44% then what is the change in the time period of the pendulum?

  • Option 1)

    22 %

  • Option 2)

    20 %

  • Option 3)

    33 %

  • Option 4)

    44 %

 

Answers (1)

As discussed in

Time period of oscillation of simple pendulum -

T=2\pi \sqrt{\frac{l}{g}}

- wherein

l = length of pendulum 

g = acceleration due to gravity.

 

 length increased by 44%.

\therefore New length = 1.44l

\therefore T^{1} = 2\pi \sqrt{\frac{1.44l}{g}} = 1.2T

i.e. Time period increased by 0.2 or 20%


Option 1)

22 %

This solution is incorrect.

Option 2)

20 %

This solution is correct.

Option 3)

33 %

This solution is incorrect.

Option 4)

44 %

This solution is incorrect.

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