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  • Solve it, If the sum of the deviations of 50 observations from 30 is 50, then the mean of these observations is :-11085

If the sum of the deviations of 50 observations from 30 is 50, then the mean of these observations is : 

  • Option 1)

    51

  • Option 2)

    30

  • Option 3)

    31

  • Option 4)

    50

Answers (1)

best_answer

 

ARITHMETIC Mean -

For the values x1, x2, ....xn of the variant x the arithmetic mean is given by 

\bar{x}= \frac{x_{1}+x_{2}+x_{3}+\cdots +x_{n}}{n}

in case of discrete data.

-

 

 

Standard Deviation -

In case of discrete frequency distribution 

\sigma = \sqrt{\frac{\sum f_{i}x_{i}^{2}}{\sum f_{i}}-\left ( \frac{\sum f_{i}x_{i}}{\sum f_{i}} \right )^{2}}

-

It should be bonus as deviations means \left | x_{i}-30 \right |  and not x_{i}-30.

Otherwise,

Given, \sum_{i=1}^{50}(x_{i}-30)=50

=>\sum x_{i}=30 (50)+50

=>\frac{\sum x_{i}}{50}=31

 

 


Option 1)

51

Option 2)

30

Option 3)

31

Option 4)

50

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