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In Young’s double slit experiment, the two slits act as coherent sources of equal amplitude A and wavelength l. In another experiment with the same set up the two slits are of equal amplitude A and wavelength l but are incoherent. The ratio of the intensity of light at the midpoint of the screen in the first case to case to that in the second case is:

  • Option 1)

    1 : 2

  • Option 2)

    2 : 1

  • Option 3)

    4 : 1

  • Option 4)

    1 : 1

 

Answers (1)

best_answer

 

Maximum amplitude & Intensity -

When \theta = 0,2\pi ---2n\pi
 

- wherein

A_{max }= A_{1}+A_{2}

I_{max }= \left ( \sqrt{I_{1}}+\sqrt{I_{2}} \right )^{2}

 

 Interference occur only in case of coherent source

I^{max} = \left ( \sqrt{I_{1}} \right+{\sqrt{I_{2}}} )^{2} = 4I

In case of incoherent source there is no interference and hence intensity at point is 2 i.

Ratio = 2:1


Option 1)

1 : 2

Incorrect

Option 2)

2 : 1

Correct

Option 3)

4 : 1

Incorrect

Option 4)

1 : 1

Incorrect

Posted by

Aadil

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