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Evaluate \int x^{-1}dx.

  • Option 1)

    x^{0}

  • Option 2)

    No\;defined

  • Option 3)

    \ln x +c

  • Option 4)

    0

 

Answers (1)

best_answer

As we have learnt,

 

Indefinite integrals for Algebraic functions -

 \frac{\mathrm{d}}{\mathrm{d} x} \frac{\left ( x^{n+1} \right )}{n+1}=x^{n} so \int x^{n}dx=\frac{x^{n+1}}{n+1}

- wherein

Where  n\neq-1

 

 \int x^{n}dx = \frac{x^{n+1}}{n+1}, for\; n \neq -1

 


Option 1)

x^{0}

Option 2)

No\;defined

Option 3)

\ln x +c

Option 4)

0

Posted by

gaurav

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