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  • Solve it, - Limit , continuity and differentiability - JEE Main-2

\lim_{x\rightarrow \pi /2^{-}}(\sin x+ \cos x)  equals 

  • Option 1)

    -1

  • Option 2)

    0

  • Option 3)

    1

  • Option 4)

    12

 

Answers (1)

best_answer

 

As we have learned

Left hand Limit -

The left hand limit of f(x) as  'x'  tends to 'a' exists and  is equal to l2  if as 'x'  approaches 'a'  through values less  than  'a'


\lim_{x\rightarrow a^{-}}f(x)= l_{2}

- wherein

Where  a-   means ( a - h )

h → 0

 

 When x\rightarrow \pi /2^{-}   then \sin x + \cos x \rightarrow 1+0 

limit = 1

 

 

 

 


Option 1)

-1

Option 2)

0

Option 3)

1

Option 4)

12

Posted by

Himanshu

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