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  • Solve it, - Limit , continuity and differentiability - JEE Main-3

\lim_{x\rightarrow 3} \frac{x^{3}-1}{x^{2}+4x} equals

  • Option 1)

    21/26

  • Option 2)

    26/11

  • Option 3)

    26/21

  • Option 4)

    26/15

 

Answers (1)

best_answer

As we have learned

Evaluation of limits : (algebraic limits) : (Method of direct substitution) -

\lim_{x\rightarrow a}f(x)\:defines\:by\:direct\:x=a


ex: \:\lim_{x\rightarrow 1}\:\frac{x^{2}+x+1}{x^{2}+x-1}=3

- wherein

Means at  x = a  f(x) defined.

 

 \lim_{x\rightarrow 3} \frac{x^{3}-1}{x^{2}+4x} = \frac{3^{3}-1}{3^{2}+4(3)}=\frac{26}{21}

 

 

 

 

 


Option 1)

21/26

Option 2)

26/11

Option 3)

26/21

Option 4)

26/15

Posted by

Himanshu

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