Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Solve it, - The force of interaction between two atoms is given by ; where x is the distance , k is the Boltzman - Physics and Measurement - JEE Main

The force of interaction between two atoms is given by F = \alpha \beta exp\left [ -\frac{x^{2}}{\alpha kt} \right ]; where x is the distance , k is the Boltzmann constant and T is temperature and \alpha and \beta are two constants. The dimensions of \beta is:

 

  • Option 1)

    M2L2T-2

  • Option 2)

    MLT-2

  • Option 3)

    ML2T-4

  • Option 4)

     

    M2LT-4

Answers (1)

best_answer

 

Check the dimensional correctness -

L.H.S.=R.H.S.

- wherein

It is based on the principle of homoginity. According to this principle both sides of an equation must be the same .

F= d\: \beta\: e\left [ \frac{-x^{2}}{dkT} \right ]

\left [ \frac{x^{2}}{dkT} \right ]= M^{o} L^{o} T^{o}

\frac{L^{2}}{[d]ML^{2}T^{-2}}= M^{o}L^{o}T^{o}

\Rightarrow [d]=M^{-1}T^{2}

[F]=[d][\beta ]

MLT^{-2}=M^{-1}T^{2}[\beta ]

[\beta ]=M^{2}LT^{-4}

 

 

 


Option 1)

M2L2T-2

Option 2)

MLT-2

Option 3)

ML2T-4

Option 4)

 

M2LT-4
Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Centre issues coaching guidelines, prohibits centres from using false claims like '100% selection'
anam-khan

BTech Admissions 2025 Live: JEE Mains, SRMJEE, VITEEE dates out; AEEE, MET registrations underway
anam-khan

BTech Admissions 2025: JEE Mains, VITEEE, SRMJEE exam dates announced

Latest Question