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  • Solve it, The Self induced emf of a coil is 25 volts, When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is :

The Self induced emf of a coil is 25 volts, When the current in it is changed at uniform rate from 10 A to 25 A in 1s, the change in the energy of the inductance is :

  • Option 1)

    437.5\: J

  • Option 2)

    740\: J

  • Option 3)

    637.5\: J

  • Option 4)

    540\: J

Answers (1)

best_answer

 

Faraday Second Law of Induction emf -

\varepsilon = \frac{-d\phi }{dt}= -L\frac{dI}{dt}

-

 

 

Energy stored in the magnetic field of the inductor -

U= \frac{1}{2}LI^{2}

-

L\frac{di}{dt} = 25

L = \frac{25\times 1}{15} = \tfrac{5}{3}

\Delta E = \frac{1}{2}\times \frac{5}{3}\left ( 25^{2}-10^{2} \right ) = 437.5

 


Option 1)

437.5\: J

Option 2)

740\: J

Option 3)

637.5\: J

Option 4)

540\: J

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