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  • Solve it, Two simple pendulums of length 5 m and 20 m respectively are given small linear displacement in one direction at the same time. They will again be in the phase when the pendulum of shorter length has completed how many oscillations

Two simple pendulums of length 5 m and 20 m respectively are given small linear displacement in one direction at the same time. They will again be in the phase when the pendulum of shorter length has completed how many oscillations

  • Option 1)

    5

  • Option 2)

    2

  • Option 3)

    1

  • Option 4)

    3

 

Answers (1)

best_answer

As learnt in

Time period of oscillation of simple pendulum -

T=2\pi \sqrt{\frac{l}{g}}

- wherein

l = length of pendulum 

g = acceleration due to gravity.

 

 T = 2\pi \sqrt{\frac{l}{g}}

N_{S} 2\pi \sqrt{\frac{5}{g}} = N_{L}\times 2\pi\sqrt{\frac{20}{g}}

\therefore N_{S} = 2N_{L}\ \ \ \ where \ \ N_{L} = 1

\therefore N_{S} = 2


Option 1)

5

This option is incorrect

Option 2)

2

This option is correct

Option 3)

1

This option is incorrect

Option 4)

3

This option is incorrect

Posted by

prateek

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