(CH_{3})_{3} C=CHCOOH\overset{A}{\rightarrow}C(H_{3})_2=CHCH_{2}OH The reagent A is

  • Option 1)

    H_{2}/Ni

  • Option 2)

    B_{2}H_{6}

  • Option 3)

    LiAlH_{4}/ether

  • Option 4)

    H_2-Pd/BaSO_4

 

Answers (1)

As we learnt in

Alcohol formation by reduction of carboxylic acids -

Yields primary alcohol.

- wherein

RCOOH+LiAlH_{4}\rightarrow RCH_{2}OH

 

 A is LiAlH4


Option 1)

H_{2}/Ni

This option is incorrect

Option 2)

B_{2}H_{6}

This option is incorrect

Option 3)

LiAlH_{4}/ether

This option is correct

Option 4)

H_2-Pd/BaSO_4

This option is incorrect

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