Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Solve! The rise in the boiling point of a solution containing 1.8 gram of glucose in 100 g of a solvent in 0.10C . The molal elevation constant of the liquid is

The rise in the boiling point of a solution containing 1.8 gram of glucose in 100 g of a solvent in  0.10C . The molal elevation constant of the liquid is

  • Option 1)

    0.01 K / m

  • Option 2)

    0.1K/m

  • Option 3)

    1K/m

  • Option 4)

    10K/m

 

Answers (1)

best_answer

As we learned 

 

Mathematical Expression -

\Delta T_{b}= K_{b}\: m

Unis of K_{b}=\frac{K-K_{g}}{mole}

\Delta T_{b}= Elevation\: in \: boiling\: point
 

- wherein

K_{b}= Boiling \: point \: elevation \: constant

m= molality

 

 K_{b}=\frac{\Delta T_{b}}{m}=\frac{0.1\times 100}{\frac{1.8}{180}\times 1000}=1K/m

 


Option 1)

0.01 K / m

Option 2)

0.1K/m

Option 3)

1K/m

Option 4)

10K/m

Posted by

Plabita

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Latest Question