Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Solve this problem A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller Given that the escape velocity from the earth is 11 km s-1, the escape velocity from the surface of the planet would be :

A planet in a distant solar system is 10 times more  massive than the earth and its radius is  10 times smaller Given that the escape velocity from the earth is  11 km s-1, the escape velocity from the  surface of the planet would be :

  • Option 1)

    0.11 km s-1

  • Option 2)

    1.1 km s-1

  • Option 3)

    11 km s-1

  • Option 4)

    110 km s-1

 

Answers (1)

best_answer

 

As we learnt in

Escape velocity - Minimum velocity which is required to escape the body from earth's gravitational pull

- wherein it is independent of the mass and direction of projection of body.

 

 V_{e}=\sqrt{\frac{2GM}{R}} for\: the \:earth

V_{e}=11kms^{-1}

mass of the planet =10Me

Radius of the planet= \frac{R}{10}

V_{e}=\sqrt{\frac{2GM\times 10}{\frac{R}{10}}}

= 10X11= 110kms^{-1}

 


Option 1)

0.11 km s-1

Incorrect option

Option 2)

1.1 km s-1

Incorrect option

Option 3)

11 km s-1

Incorrect option

Option 4)

110 km s-1

Incorrect option

Posted by

prateek

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2025 session 1 registration deadline on November 22; apply on jeemain.nta.nic.in
anam-khan

BTech Admission 2025 Live: JEE Mains, SRMJEEE, MET registrations underway; MHT CET syllabus updates
anam-khan

Centre issues coaching guidelines, prohibits centres from using false claims like '100% selection'

Latest Question