# A planet in a distant solar system is 10 times more  massive than the earth and its radius is  10 times smaller Given that the escape velocity from the earth is  11 km s-1, the escape velocity from the  surface of the planet would be : Option 1) 0.11 km s-1 Option 2) 1.1 km s-1 Option 3) 11 km s-1 Option 4) 110 km s-1

As we learnt in

Escape velocity - Minimum velocity which is required to escape the body from earth's gravitational pull

- wherein it is independent of the mass and direction of projection of body.

$V_{e}=\sqrt{\frac{2GM}{R}} for\: the \:earth$

$V_{e}=11kms^{-1}$

mass of the planet =10Me

Radius of the planet= $\frac{R}{10}$

$V_{e}=\sqrt{\frac{2GM\times 10}{\frac{R}{10}}}$

= 10X11= 110$kms^{-1}$

Option 1)

0.11 km s-1

Incorrect option

Option 2)

1.1 km s-1

Incorrect option

Option 3)

11 km s-1

Incorrect option

Option 4)

110 km s-1

Incorrect option

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