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  • Solve this problem - Co-ordination Compounds - JEE Main-3

The oxidation number of Cr in [Cr(NH_{3})_{6}]Cl_{3} is

  • Option 1)

    8

  • Option 2)

    6

  • Option 3)

    4

  • Option 4)

    3

 

Answers (1)

best_answer

As we have learned

Oxidation number -

It is represented by roman numeral in parenthesis following the name of coordination entity.

- wherein

Eg. [Cu(CN)_4]^2^-

x-4 = -2

x= 2

 

 x+6*(0)+3*(-1)=0

x-3 =0 , x= +3 

Oxidation number of Cr is = +3

 

 

 

 


Option 1)

8

Option 2)

6

Option 3)

4

Option 4)

3

Posted by

satyajeet

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